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I took the approach I saw in my class: $$y = 0.3f(5(x-3)) = 0.3f(5x-15)$$ $$(x, y) \mapsto (5x-15, 0.3y)$$ $$(2, 1) \mapsto (5(2)-15, 0.3(1)) = (-5, 0.3)$$

The problem is that my textbook says that $(3.4, 0.3)$ is the solution. I haven't a clue as to where I went wrong, so maybe someone on here can help?

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1 Answer

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We know that

$$f(2)=1$$

Hence, to find a point that satisfies $y=0.3f(5(x-3))$

I shall let $$5(x-3)=2$$

Exercise: Solve for $x$.

Then $y=0.3f(2)=0.3$

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