Glam Prestige Journal

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maclaurin series of $f(x)=xe^{-x}$

I'm not sure how to do: $$f(x)=xe^{-x}$$I did this one so far: $$ f(x) = x^2 \cos x = x^2 \left( 1 - \dfrac{x^2}{2!} + \dfrac{x^4}{4!} - \dfrac{x^6}{...

Apr 14, 2026