How to approximate $\pi$ using the Maclaurin series for $\sin(x)$
We have that $$\sin(x)=x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots$$ Now plugging in $x=\pi$, $$0=\pi - \frac{\pi^3}{3!} + \frac{\pi^5}{...
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We have that $$\sin(x)=x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots$$ Now plugging in $x=\pi$, $$0=\pi - \frac{\pi^3}{3!} + \frac{\pi^5}{...
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