I have the question
Computer keyboard failures can be attributed to electrical defects or mechanical defects. A repair facility currently has 25 failed keyboards, 6 of which have electrical defects and 19 of which have mechanical defects
A) In how many ways can a sample of 5 keyboards be selected so that exactly two have an electrical defect?
B) If a sample of 5 keyboards is random selected, what is the probability that at least 4 of these will have a mechanical defect?
For A - I know i have to use combinations, but i'm not sure what the numbers are.
Could anyone begin to point me in the right direction? Thanks!
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$\begingroup$B) If a sample of 5 keyboards is random selected, what is the probability that at least 4 of these will have a mechanical defect?
$$P = \frac{{19\choose 4}+{19\choose 5}}{25 \choose 5}$$
$\endgroup$ 1 $\begingroup$$\newcommand{\ch}[2]{{^{#1}\mathsf C_{#2}}}$
A. From the 6 keyboards that have electrical defects, choose 2. From the 19 keyboards that have mechanical defects, choose 3. $$\ch6 2 \cdot \ch {19}3$$
B. From the 19 keyboards that have mechanical defects, choose 4 then from 6 keyboards that have electrical defects, choose 1. Add it to: from the 19 keyboards that have mechanical defects, choose 5. All over from 25 keyboards that have defects, choose 5. $$\dfrac{\ch{19}4 \cdot \ch{6}{1} + \ch{19}5}{\ch{25}5}$$
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