Evaluate the piecewise defined function

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Evaluate the piecewise defined function at the indicated values.

$f(x) = \begin{cases} 3 & \text{x≤5} \\ 5x-6, & \text{if x>5} \end{cases}$

$f(−6) = -6$

$f(0) = 0 $f(5) = 5

$f(6) = 24 $

$f(8) = 34 $

Are my answers correct?

Thank you

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The three first are wrong :

$f(-6)=f(0)=f(5)=3$ because $-6\leq0\leq5$

The two last one are correct :

$f(6)=5\times6-6=24$ because $6\geq5$

$f(8)=5\times8-6=34$ because $8\geq5$

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The last two are correct. You are doing something very wrong for the first three, but I don't know what because you have given no working.

You need to pay close attention to the ranges to which each piece of the function applies.

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