I'm wondering how many possible 3 character combinations can be made using the 26 letters of the alphabet, and 0-9. I've seen that with just the alphabet you can create somewhere around 17k different combinations of 3 letters, but I assume adding in 0-9 must increase that number substantially.
$\endgroup$ 23 Answers
$\begingroup$Well, there are 36 combinations for each, and they're all independent. 36x36x36 is 46656.
$\endgroup$ $\begingroup$Assuming we're choosing from 26 letters and 10 digits, such that the case of the letters doesn't matter and repetition is allowed, you have
$$36 \times 36 \times 36$$
arrangements, since you have 36 choices each. If letter case matters, then
$$62 \times 62 \times 62$$.
$\endgroup$ $\begingroup$Deusovi is correct if characters can be repeated. If not then 36x35x34 combinations are possible.
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