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I don't get it. How do I get information from the graphs? How can it be solved?

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1 Answer

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$a_x$ is the slope of first graph, so $a_x=3$.

$a_y$ is the slope of second graph, so $a_y=-3$.

Then $\vec{a}=3\vec{i}-3\vec{j}$ and $\vec{F}=m\vec{a}=3.3(3\vec{i}-3\vec{j}) N$ from here $|\vec{F}|=9.9\sqrt{2}\,N$.

It's direction $\tan\theta=\dfrac{-3}{3}=-1$ then $\theta=-45^\circ$.

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