How to use grep to find the next 7 characters after "temp1"?

how can i get "+45.0°C" if the following output was a file ()?

I can get it to one line by doing

sensors -A acpitz-virtual-0 > sen
grep temp1 ~/sen

but it still has a load of useless crap on it:

"temp1: +42.0Â°C (crit = +90.0Â°C)"

2 Answers

Here's the answer: For instance these are the texts inside the file

acpitz-virtual-0
Adapter: Virtual device
temp1: +45.0Â°C (crit = +90.0Â°C)
temp2: +45.0Â°C (crit = +90.0Â°C)

To get the +45.0Â°C of temp1, use this command:

grep temp1 < theFileWithTemp.txt | awk '{print $2}'

You may use egrep (or grep -e) to use regular expressions. With .{7} 7 arbitrary characters:

echo -e "temp1:\t+42.0°C (crit = +90.0°C)" | egrep -o "temp1:.{7}"
temp1: +42.

With -o you restrict the output to your match. To cut off just the rest of the line:

 echo -e "temp1:\t+42.0°C (crit = +90.0°C)" | egrep -o "temp1:.{7}" | egrep -o ".{5}$"