I have this kind of html tag, which is interrupted by space at some point after word masuri:
<p>Aceasta este o melodie alcatuita din patru masuri:
reluata apoi de catre instrumentul solist cu un cintec popular.</p>THE OUTPUT:
<p>Aceasta este o melodie alcatuita din patru masuri: reluata apoi de catre instrumentul solist cu un cintec popular.</p>I want to replace the newline character in that particular tag <p></p>
I find an old regex made by @Toto, seems good, but doesn't make the replacement in order to get the output:
FIND: (?:<p>|\G)(?:(?!</p>).)*?\s\K\s+
REPLACE BY: (leave empty)
2 Answers
I simply make the assumption based on your desired output that you want to replace a newline character instead of a space.
This will match any single occurence of a newline inside of the specified tag:
(<p>)+(.)+\K(\r\n|\r|\n)(?=.*<\/p>)
Explanation:
(<p>)+(.) matches the opening tag + any character that follows
\K resets the matches
(\r\n|\r|\n) matches the newline character
(?=.*<\/p>) checks for any character +
So, the regex that removes newsline is (?<=[^\r\n])\R(?=[^\r\n]). I put this regex in this new regex formula, at the end. See also below the source of how I manage to resolve the problem.
Use the following:
- Ctrl+H
- Find:
(?-i:<p>|(?!\A)\G)(?s:(?!</p>).)*?\K(?-i:(?<=[^\r\n])\R(?=[^\r\n])) - Replace with:
\x20 - CHECK Match case
- CHECK Wrap around
- CHECK Regular expression
- UNCHECK
. matches newline - Replace all
I resolve this problem by reading this topic:
I fully endorse your new abbreviations ! So :
Let FR (Find Regex ) be the regex which defines the char, string or expression to be searched
Let RR (Replacement Regex ) be the regex which defines the char, string or expression which must replace the FR expression
Let BSR ( Begin Search-region Regex ) be the regex which defines the beginning of the area where the search for FR, must start
Let ESR ( End Search-region Regex) be the regex which defines, implicitly, the area where the search for FR, must endThen, the generic regex can be expressed :
SEARCH: (?-i:BSR|(?!\A)\G)(?s:(?!ESR).)*?\K(?-i:FR)
REPLACE: RR
