I was studying calculus and I had doubts about this problem: (this is not homework)
A circular wire expands due to heat so that its radius increases with a speed of $0.01 ms^{-1}$. How rapidly does the area increase when the radius is 2 cm?
The solution goes like this:
Let x be the radius and y the area. Then:
$$y=\pi x^2$$
And then it goes like this:$${dy\over{dt}}=2\pi x {dx\over{dt}}$$How is this possible to do? y is a single variable function and x is just the independent variable.
This confuseses me a lot.
$\endgroup$1 Answer
$\begingroup$No this is why you should have never been taught that $f(x)$ means $y = ...$. Both $y$ and $x$ are functions of $t$:
$$ y(t) = \pi x^2(t) $$
Now differentiate both sides with respect to $t$--use the chain rule:
$$ \frac{d}{dt}y(t) = \frac{d}{dt}\left(\pi x^2(t)\right) \\ \frac{dy}{dt} = 2\pi x \frac{dx}{dt} $$
Here is another way to look at it:
$$ y = f(x) \\ \frac{dy}{dt} = \frac{df}{dt} = \frac{df}{dx}\frac{dx}{dt} $$
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